Jump to content
JovanR

⚡ [$800] The Greatest Minds: Michael Faraday ⚡

Recommended Posts

image-png-caf8826ed4a8d4db08347a5c466e9cimage.png

 👨🏻‍🔬⚡ The Greatest Minds: Michael Faraday  ⚡👨🏻‍🔬

Ends: 31/05/2021 @ Midday (02pm) GMT 
  

Spoiler

Michael Faraday 

Was an English scientist who contributed to the study of electromagnetism and electrochemistry. His inventions of electromagnetic rotary devices formed the foundation of electric motor technology, and it was largely due to his efforts that electricity became practical for use in technology. As a chemist, Faraday discovered benzene, investigated the clathrate hydrate of chlorine, invented an early form of the Bunsen burner and the system of oxidation numbers, and popularised terminology such as "anode", "cathode", "electrode" and "ion". Faraday ultimately became the first and foremost Fullerian Professor of Chemistry at the Royal Institution, a lifetime position.

"There's nothing quite as frightening as someone who knows they are right."

All players who complete the challenge in the next 7 days, will get a share in the prize pool! There is no limit to the number of winners, and the more people who get involved, the higher the prize pool! So if you get more people involved, then you win more!

 

 

Requirements:

  • Win two bets with 40x and 8x multiplier.
  • Bets have to be in a row (consecutive).
  • One of the Bet IDs has to have number 48 anywhere. 
  • 0.03 USD minimum bet amount (in any currency).

Tips & Terms & Conditions

  • 1 valid entry per household.
  • Bets must have been made after the commencement of this promotion.
  • Do not change your linked account during the whole duration of the promotion.
  • 10+ forum post count.
  • Primedice employees can not participate in official Primedice.com forum challenges. This does not apply to moderators.
  • Haven't broken any General Giveaways Rules!

Prize Pool(s)

  • Minimum prize pool: $150
  • If over 30 participants: $350
  • If over 50 participants: $450
  • If over 100 participants: $550
  • If over 200 participants: $800

How to Enter

  1. Respond to this topic, and link your bet IDs using the link function in the text editor. Feel free to edit your posts as you catch the new bets. 

(Paste your bet id, then highlight and click on the link bet button, as shown in the image below)
 

image.png

Share this post


Link to post
Share on other sites

placed by Serlite on 24/05/2021

Wagered

0.00018267ltc.svg

Multiplier

39.92x

Profit

0.00710940ltc.svg

placed by Serlite on 24/05/2021

Wagered

0.00018267ltc.svg

Multiplier

8.00x

Profit

0.00127810ltc.svg

Pretty straightforward challenge, though it can be cumbersome if you don't have a script. So here's the one I wrote!

Note how there's no logic in there to hunt for the specific bet ID digits - that's because the most efficient way to do this challenge is to only bet when you know there will be a "48" in the bet ID. You can guarantee that by waiting until a "48" occurs in a high enough digit that it won't change for a while, then start betting. Remember to stop betting before those digits change, and wait for your next chance.

nextbet  = 0.00018267
bethigh  = true
currency = "Ltc"

local multipliersToHunt = {40, 8}
local winStreak         = 0

function dobet()
    if win then
        local multiplier = convertToMultiplier(chance)
        print ("Hit for " .. multiplier .. "x multiplier!")

        if winStreak + 1 == #multipliersToHunt then
            ching()
            stop()
        else
            winStreak += 1
            chance = getChance()
            print ("Continuing hunt to " .. multipliersToHunt[winStreak + 1] .. "x multiplier.")
        end
    else
        winStreak = 0
        chance    = getChance()
    end
end

function getChance()
    return convertToWinChance(multipliersToHunt[winStreak + 1])
end

function convertToWinChance(multiplier)
    return round(99 / multiplier, 2)
end

function convertToMultiplier(winChance)
    return 99 / winChance
end

function round(x, decimalPlaces)
    local mult = 10^(decimalPlaces or 0)
    return math.floor(x * mult + 0.5) / mult
end

chance = getChance()

 

Share this post


Link to post
Share on other sites
Guest
This topic is now closed to further replies.

×